percentile
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- | ====== 百分位数、百分位等级、插值法 ====== | + | ====== 百分位数、百分位等级、插值法 |
- | ---- | + | ===== 百分位数、百分位等级 |
- | ===== 一.百分位数、百分位等级 ===== | + | |
- | **1.百分位等级 (// | + | |
- | **2.百分位数 (// | + | ==== 百分位等级 (Percentile rank) ==== |
+ | |||
+ | 某一分布中, | ||
+ | In a distribution, | ||
+ | |||
+ | ====百分位数 (Percentile) ==== | ||
+ | |||
+ | 恰取这一值的分数称为这一百分位等级的百分位数。\\ | ||
+ | The score that takes exactly this value is called the percentile of this percentile rank. | ||
+ | |||
+ | ==== 例子 (Example) ==== | ||
+ | |||
+ | 有 58% 的同学分数为 7 分或在 7 分下,则分数 | ||
+ | If 58% of the students have a score of 7 or below, the percentile rank of X=7 is 58% , so the X=7 is the 58th percentile. | ||
+ | |||
+ | ==== 注意事项 (Notes) ==== | ||
+ | |||
+ | 在某一个案例中,分数有 1 - 5 分,对于分数 4 , 算得其对应的累积百分比是 95% ;但注意,分数 4 意味着一个人得分在 3.5 和 4.5 之间,第 95 百分位数是 4.5 ,而不是 4.0 。\\ | ||
+ | In one case, the score is 1 - 5 , and for a score of 4 , the corresponding cumulative percentage is 95% ; but note that a score of 4 means that a person scores between 3.5 and 4.5 , and the 95th percentile is 4.5 , not 4.0 . | ||
- | **3.例子:**有58%的同学分数为7分或在7分下,则分数X=7的百分位数等级为58%,这个分数就是第58个百分位数。 | ||
- | |||
- | **4.如何确定百分位数:**\\ | ||
- | 对于分数4, | ||
- | 但注意:分数4意味着一个人得分在3.5 和 4.5之间. 累积百分比表明组距的精确上限。因此,95 的百分位数是与4.5 相对应(而不是 4.0) | ||
---- | ---- | ||
- | ===== 二.插值法 ===== | + | ===== 插值法 |
- | **1.插值法 | + | |
- | 插值法的假设是在所求解点的附近1个组距单位区间之内的分数和对应的百分比的变化是线性的。 | + | 插值法是一种求解两个数值之间某位置数值的方法,其假设是在所求解点的附近1个组距单位区间之内的分数和对应的百分比的变化是线性的。\\ |
+ | Interpolation is a method to calculate the value of a certain number between two numbers. The hypothesis of interpolation is that, the change in scores and percentages within a unit interval of 1 group distance around the solved point is linear. | ||
+ | |||
+ | ==== 插值法步骤 (The steps of interpolation) ==== | ||
+ | |||
+ | 假设要求的数值如图所示:\\ | ||
+ | Suppose the value to be solved is shown as follows: | ||
- | **2.插值法步骤:**\\ | + | {{ :第二章:2.5:插值法1.svg |}} |
- | 假设要求的数值如图所示 | + | |
- | {{: | + | 1. 找到距求解点最近的两个区间(较远的区间不满足分数和对应的百分比线性变化的假设)。\\ |
+ | Find the 2 nearest intervals to the value to be solves (Further intervals do not requires the hypothesis of scores and percentages changing linearly). | ||
- | (1)找到距求解点最近的两个区间(较远的区间不满足分数和对应的百分比线性变化的假设) | + | 2. 根据数据列出方程:\\ |
+ | Make an equation based on the data: | ||
- | (2)根据数据列出数据:\\ | + | {{ : |
- | {{: | + | |
- | (3)由等式求得x=56 | + | 3. 由等式求得结果 {{: |
+ | Calculate the equation, and get the result of {{: |
percentile.1677759754.txt.gz · 最后更改: 2023/03/02 12:22 由 空白不灭